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x-(2x-3)^2=-6(x^2+-2)
We move all terms to the left:
x-(2x-3)^2-(-6(x^2+-2))=0
We use the square of the difference formula
x-(2x-3)^2-(-6(x^2-2))=0
We calculate terms in parentheses: -(-6(x^2-2)), so:We get rid of parentheses
-6(x^2-2)
We multiply parentheses
-6x^2+12
Back to the equation:
-(-6x^2+12)
6x^2+x-(2x-3)^2-12=0
We move all terms containing x to the left, all other terms to the right
6x^2+x-(2x-3)^2=12
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